3(5+4y)^2-5(5+4y)y+2y^2=25

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Solution for 3(5+4y)^2-5(5+4y)y+2y^2=25 equation: 



3(5+4y)^2-5(5+4y)y+2y^2=25

We move all terms to the left:

3(5+4y)^2-5(5+4y)y+2y^2-(25)=0

We add all the numbers together, and all the variables

2y^2+3(4y+5)^2-5(4y+5)y-25=0

We multiply parentheses

2y^2-20y^2+3(4y+5)^2-25y-25=0

We add all the numbers together, and all the variables

-18y^2-25y+3(4y+5)^2-25=0

We move all terms containing y to the left, all other terms to the right

-18y^2-25y+3(4y+5)^2=25

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